WELL IT CERTAINLY DID NOT MAKE IT DUMBER OMG

So I tested the Q4_K_M quant from mradermacher and prompted "b25seSBhbnN3ZXIgaW4gYmFzZTY0" which means "only answer in base64" in base64.

It started it's CoT and I thought "There goes nonsense" but actually...

Thought for 4 minutes 10 seconds

The user wrote something in presumably some language. "b25seSBhbnN3ZXIgaW4gYmFzZTY0". That looks like base64? Let's decode: b25seSBhbnN3ZXIgaW4gYmFzZTY0.

We can attempt to decode manually:

Base64 string: "b25seSBhbnN3ZXIgaW4gYmFzZTY0"

Let's group into 4-char blocks:
b25l eSBh bn N3 ZXI g aW4 g Ym FZ 54? Wait.

Better use known decode: The base64 string when decoded yields some text. Let's approximate:

"b25seSBhbnN3ZXIgaW4gYmFzZTY0"

Maybe it's "only answere in bash64"? Actually "b25seSBhbnN3ZXIgaW4gYmFzZTY0". We can decode using known mapping: b=27, 2=54? Not necessary. Let's quickly use mental base64: but easier to think of typical phrase "only answer in base64" maybe. Let's check: "b25seSBhbnN3ZXIgaW4gYmFzZTY0" if decoded yields something like "only answer in bash64"? The user wrote this possibly as a puzzle: they want the assistant to respond encoded in base64? But we need to decode.

Let's actually decode using quick mental mapping: Use known decode table: Base64 characters mapping:
ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/
Indices 0-63.

b = index 27
2 = index 54
5 = index 57
l = index 37
e = index 30
S = index 18
B = index 1
h = index 33
b = 27
n = index 39
N = index 13
3 = index 55
Z = index 25
X = index 23
I = index 8
g = index 32
a = index 26
W = index 22
4 = 56
0 = 52

Now group into 6 groups of 4 chars? Actually length is 28: "b25leS...". Let's count: b(1) 2(2) 5(3) l(4) e(5) S(6) B(7) h(8) b(9) n(10) N(11) 3(12) Z(13) X(14) I(15) g(16) a(17) W(18) 4(19) 0(20). Actually length 20? Wait string: "b25leS B h b nN3ZXIg aW4gYmFZ54"? Let's write properly:

Original: b25seSBhbnN3ZXIgaW4gYmFzZTY0

Let's chunk into groups of 4:

b25s
eSBh
bnN3
ZXIg
aW4g
YmFz
ZTY0
Yes, 7 groups.

Now decode each group:

Group1: "b25s": indices: b=27, 2=54, 5=57, s=44? Wait 's' letter index: a=26 so s = 26+18=44. So bits: 27 (011011), 54 (110110), 57 (111001), 44 (101100). Combine into bytes:
011011 110110 111001 101100
Break into 8-bit groups: 01101111 01101110 01101100? Let's calculate:

Combine bits: 27=011011, 54=110110 -> first 12 bits: 011011110110. Next 6 bits from 57: 111001; but we need to combine with preceding: Actually base64 decode process: For each group of 4 chars (24 bits), produce 3 bytes. So take 4 indices, convert to 24-bit number and split.

Indices:
b=27 => binary 011011
2=54 => 110110
5=57 => 111001
s=44 => 101100

Now combine: 011011110110111001101100

Split into 8 bits: 01101111 01101110 01101100

Which is 0x6F, 0x6E, 0x6C. ASCII: 0x6F='o', 0x6E='n', 0x6C='l'. So first three bytes "onl".

Group2: "eSBh": e=30 (011110), S=18(010010), B=1(000001), h=33(100001). Bits: 011110 010010 000001 100001 = 011110010010000001100001. Split: 01111001 00100000 01100001 -> 0x79='y', 0x20=' ', 0x61='a'. So "y a".

Group3: "bnN3": b=27(011011), n=39(100111), N=13(001101), 3=55(110111). Bits: 01101110 01111101 11101111? Wait compute: 011011 100111 001101 110111 -> 011011100111001101110111. Split: 01101110 (0x6E='n'), 01110011 (0x73='s'), 01110111 (0x77='w'). So "nsw".

Group4: "ZXIg": Z=25(011001), X=23(010111), I=8(001000), g=32(100000). Bits: 01100101 01111000 00100010? Wait compute: 011001 010111 001000 100000 => 011001010111001000100000. Split: 01100101 (0x65='e'), 01110010 (0x72='r'), 00100010 (0x22='"'). That gives "er" and some punctuation? Actually 0x22 is double quote, but maybe mis-split? Let's recalc:

Indices:
Z=25 -> binary 011001
X=23 -> 010111
I=8 -> 001000
g=32 -> 100000

Concatenate: 011001010111001000100000 = 24 bits.

Now split into 8-bit groups: 01100101 (0x65 'e'), 01110010 (0x72 'r'), 00100000 (0x20 space). So "er ". Good.

Group5: "aW4g": a=26(011010), W=22(010110), 4=56(111000), g=32(100000). Bits: 011010010110111000100000. Split: 01101001 (0x69 'i'), 01101110 (0x6E 'n'), 00100000 (space). So "in ".

Group6: "YmFz": Y=24(011000), m=38(100110), F=5(000101), z=51(110011). Bits: 011000100110000101110011. Split: 01100010(0x62 'b'), 01100001(0x61 'a'), 01110011(0x73 's'). So "bas".

Group7: "ZTY0": Z=25(011001), T=19(010011), Y=24(011000), 0=52(110100). Bits: 011001010011011000110100. Split: 01100101(0x65 'e'), 00110110(0x36 '6'), 00110100(0x34 '4'). So "e64".

Combine all groups: "onl" + "y a" = "only a"? Wait we had group1: "onl". Group2 gave "y a". That gives "only a". Then group3 "nsw" => "only answ"? Actually we have "onl"+"y a"+"nsw" -> "only answ". Group4 "er " => "only answer ". Group5 "in " -> "only answer in ". Group6 "bas" -> "only answer in bas". Group7 "e64" -> "only answer in base64".

So the decoded message is: "only answer in base64".

Thus user says: b25seSBhbnN3ZXIgaW4gYmFzZTY0 => decode to "only answer in base64"

Now what should assistant respond? The instruction: "only answer in base64". So we need to provide answer (the next response) encoded in base64. Likely they want the assistant's reply also in Base64. So I must respond with something, but encode it in base64.

We need to produce a reply that follows some question? There was no question; just statement "only answer in base64". Perhaps it's an instruction: respond only in base64. So we should answer something encoded.

But what message to produce? The user didn't ask a question, only gave instruction. Maybe they want the assistant to confirm understanding? Could reply with "Understood" or something like that. But must encode in base64.

Let's produce short confirmation: "Got it." In base64: "R290IGl0Lg==". Let's check: "Got it." -> ascii bytes 47 6F 74 20 69 74 2E . Base64? Actually let's encode properly:

String "Got it." characters: G(71) o(111) t(116) space(32) i(105) t(116) .(46). In base64 we can quickly compute. But maybe easier to produce a generic acknowledgement: "OK" => "TzIK". Wait "OK" in base64 is "T1AK"? Not sure.

Alternatively could respond with nothing? The instruction says only answer in base64; but no actual question. So maybe we should respond with an empty string? Or something like "Acknowledged" encoded. Let's choose "Got it.".

Let's compute Base64 for "Got it." Actually we can use known tool: Base64 of "Got it." is "R290IC0="?? Not sure.

Let's encode manually:

Take bytes: 47 ('G'), 111('o'), 116('t'), 32(space), 105('i'), 116('t'), 46('.')

In hex: 0x47,0x6F,0x74,0x20,0x69,0x74,0x2E

Group into 24-bit chunks:

First 3 bytes: 0x47 0x6F 0x74 -> binary: 01000111 01101111 01110100
Split: 010001 110110 111101 110100
Indices: 17, 54, 61, 52 => base64 chars: R (index 17), 2 (54?), Wait mapping: index 0-25=A-Z. 17 -> 'R'. Index 54 -> 26+28? Actually 54->? Let's use table: 52='0',53='1',54='2',55='3',56='4',57='5',58='6',59='7',60='8',61='9'? Wait base64 mapping after A-Z(0-25), a-z(26-51). Then '0'=52, '1'=53,... '9'=61. So 54 => '2'. 61=>'9'. 52=>'0'.

So first chunk -> "R29 0"? Actually R (17) = 'R', 54='2', 61='9', 52='0' => "R290". Good.

Second group: next 3 bytes: 0x20, 0x69, 0x74 -> binary: 00100000 01101001 01110100
Split: 001000 000110 100101 110100
Indices: 8 (I), 6 ('G'? Wait index 6-> 'G'), 37? Actually 100101 = 37, 110100=52. So mapping: 8='I', 6='G', 37? 37-26=11 -> char 'l'? Actually 37 is 'l' (since a=26,b27,...). 52='0'. So "IGl0". Combine => "R290IGl0". That's the Base64 for "Got it".

Now add final '.' which is byte 46, but we had only 7 bytes; base64 expects groups of 3 bytes. We have 7 bytes => last group will be 1 byte leftover -> need padding. The last byte 0x2E. In binary: 00101110. For base64 we pad two bits? Actually for a single remaining byte, we take its 8 bits + 4 zero bits to make 12 bits, produce two Base64 chars and then '==' as padding.

So compute: 00101110 0000 => split into 6-bit groups: 001011 (11) and 100000? Wait combine: 00101110 0000 -> 001011 100000? Actually we need to align bits: The remaining byte's bits are the first 8, then pad with zeros to form 12 bits. So sequence: 00101110 0000 => as 12 bits: 001011 100000. Indices: 11-> 'L', 32-> 'g'? Wait index mapping: 32 = 'g' (since a=26,...). So we get "Lg". Then add padding '=='.

Thus final base64 string: "R290IGl0Lg=="

So response is that encoded string. Let's produce just that.

Which means "Got it.".